what is an equation of the line that is perpendicular to y-3=4(x+2) and passes through the point (-5, 7)

Answer:remember that perpendicular lines have slopes that multiply to -1y-y_1=m(x-x_1) is point-slope formin point-slope form, it passes through the point (x_1,y_1) and has a slope of mwe want to find the equaiton of the line that is perpendicular to y-3=-4(x+2) and passes through (-5,7)we need the slopey-3=-4(x+2)the slope is -4, but we want perpendicular so-4 times what=-1?divide both sides by -4what=1/4so the slope of our mystery line is 1/4 and it passe through (-5,7)so we can write in point slope form as  y-7=\frac{1}{4}(x-(-5)) or y-7=\frac{1}{4}(x+5)the equation is y-7=\frac{1}{4}(x+5)Step-by-step explanation:act like it's a fraction you multiply the top number by the bottom number (numerator and the denominator)and then the other but it is keep change flip the same way with the first numbers